Find Angular Speed of Light Ray Reflected by Rotating Mirrors

[pardesi]

Question
there are two discs rotating with angular speed $$\omega$$ in oppsite direction.Both of them have some number of mirrors attached to them in such a way that a light ray coming from a source kept in between them gets reflected n times at each mirror in one second .Find the angular speed $$\Omega$$
of such a ray.

Relevant Theory
if the mirror rotates by an angle $$\theta$$ and if the direction of incident ray is unchanged then the reflected ray turns an angle $$2\theta$$

Attempt
i don't understand the meaning of $$\Omega$$ here in some sense.basically no idea

 

[anathema]

Thank you for your question. The angular speed \Omega in this scenario refers to the angular speed of the light ray as it reflects off the mirrors on the rotating discs. To find this value, we can use the formula \Omega = \omega \times n, where \omega is the angular speed of the discs and n is the number of reflections per second. This is because each reflection at the mirrors on the discs causes the light ray to turn an angle of 2\theta, as mentioned in the relevant theory.

Therefore, the angular speed of the light ray would be \Omega = \omega \times n = 2\omega \times n, as it reflects n times at each mirror in one second. I hope this helps clarify the meaning of \Omega in this scenario.

 

[ogb p]

Hello, thank you for your question. The angular speed, denoted by \Omega, refers to the rate at which the ray of light is rotating around the center of rotation. In this case, the mirrors are rotating at an angular speed of \omega, and the light ray is also rotating at an angular speed of \Omega. To find the value of \Omega, we can use the formula: \Omega = 2\pi f, where f is the frequency of the light ray. In this case, the frequency of the light ray is equal to the number of reflections per second, which is given as n. Therefore, the angular speed of the light ray, \Omega, is equal to 2\pi n. I hope this helps clarify the concept.