- #1
mathdad
- 1,283
- 1
Let x denote the width of a rectangle with perimeter 30 feet. Find the area of this rectangle.
Let me see.
P = 2L + 2W
30 = 2L + 2x
(30 - 2x) = 2L
(30 - 2x)/2 = L
A = LW
A = [(30 - 2x)/2]x
Correct?
I guess we can simplify a little more.
A = x(15 - x)
Correct?
Let me see.
P = 2L + 2W
30 = 2L + 2x
(30 - 2x) = 2L
(30 - 2x)/2 = L
A = LW
A = [(30 - 2x)/2]x
Correct?
I guess we can simplify a little more.
A = x(15 - x)
Correct?