Find Charge in Sphere: Integrate \rho(r)

AI Thread Summary
In a sphere with a varying charge density of ρ(r) = Br^N, the task is to find the charge enclosed for r < R. The integration of the charge density leads to a formula for charge, but there is confusion regarding boundary conditions. It is clarified that the relevant condition for finding charge is at r = 0, not r = R, since charge exists within the sphere. When considering r > R, the charge is effectively zero, as the charge density does not extend beyond the sphere's surface. Understanding these conditions is crucial for accurately calculating the charge enclosed.
YoGabbaGabba
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Homework Statement


In a sphere of radius R, the charge density varies as \rho(r) = BrN. There is no charge outside the sphere. B and N are constants.

a.) Find the charge enclosed in a sphere of radius r<R.

Homework Equations


\rho=dq/dv

The Attempt at a Solution


I integrated \rho(r)(4\pir2dr) and got q=(4\piBrN+3)/(N+3) + C. Is this right? If so, would it be correct to use the boundary condition; @ r=R, q=0 in order to solve for C? It doesn't sound right because there must be charge at the surface?
 
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Hi YoGabbaGabba, welcome to PF,
You are required to find the field at r<R. So you need not the condition r = R. Instead you can take the condition q = 0 at r = 0.
 
Thanks for your time. So if asked to find the charge when r>R, is the charge simply zero or do we consider the boundary conditions r=R? Thanks.
 
YoGabbaGabba said:
Thanks for your time. So if asked to find the charge when r>R, is the charge simply zero or do we consider the boundary conditions r=R? Thanks.
Charge density cannot be zero between r = 0 to r = R. And asking to find the charge density when r > R is meaning less.
 
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