- #1
JWest
- 12
- 0
Find the dx for an object projected at 100 m/s from 20 degrees to 70 degrees in 5 degree intervals. How would you exactly do this? Would you use the equation Ay = A sin X?
Skotster said:break up your Vi=100m/s at 20 degrees into the x&y components
Vix=Vi*cos(20 degrees)
Viy=Vi*sin(20 degrees)
assuming you are on Earth and ingoring air friction
use
Vf=Vi+(-9.8m/s^2)*t
to get
t=(Vf-Vi)/(-9.8m/s^2)
lettin Vf=0 to find time to max height
double it to get the total air time
use total time in
dx=Vix*t
The formula for finding dx in this scenario is dx = v0 * cos(theta) * t, where v0 is the initial velocity, theta is the launch angle, and t is the time.
The time (t) can be calculated using the formula t = (2 * v0 * sin(theta)) / g, where g is the acceleration due to gravity (9.8 m/s^2).
The unit of measurement for dx is meters (m), as it represents the horizontal distance traveled by the object.
Yes, this equation can be used as long as the initial velocity and launch angle are known. However, it is important to note that the equation assumes a flat, uniform gravitational field.
This equation provides a simplified calculation and does not take into account factors such as air resistance and other external forces. Therefore, its accuracy may vary in real-world scenarios and should be used as an estimate rather than an exact measurement.