Find Spring Constant: Prove 1/K_eff = 1/k_1 + 1/k_2

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To prove the relationship 1/K_eff = 1/k_1 + 1/k_2 for a system with two springs, consider the forces acting on each spring, where F1 = -k1*x1 and F2 = -k2*x2. The total force must equal zero, leading to the equation F1 + F2 = 0, which implies that the force on both springs is equal. By expressing the resultant force as F_r = -K_eff*(x1 + x2), the relationship can be established. The discussion emphasizes that the effective spring constant K_eff can be derived by recognizing that the force is consistent across both springs, allowing for the application of the combined displacement. Understanding this principle simplifies the process of finding K_eff.
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Finding the given spring constant

Homework Statement




Consider the system represented on the figure, constituted by the mass m and two springs of constant k1 and k2.
(The image is attached)
Prove that:

\frac{1}{K_{eff}} = \frac{1}{k_{1}} + \frac{1}{k_{2}}

Homework Equations



F = -kx

The Attempt at a Solution



I don't know where to begin. I have to consider two different displacements: One for the first spring, and one for the second.
I think, but I am not sure, that I can consider both forces are equal.
So:

F1 = -k_{1} x_{1}

F2 = -k_{2} x_{2}

and

1)

F1 + F2 = 0

and a resultant force =

F_{r} = -k_{eff} x

2)

x = x1 + x2

I tried making a system with equations 2 and 1, but I am getting nowhere. Can anyone help?
 

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The force on both springs are equal i.e. F1=F2

Now the force on one spring is also equal to keff(x1+x2).

I think you can now find keff
 
rock.freak667 said:
Now the force on one spring is also equal to keff(x1+x2).

can you explain why is that so, please?
 
Fanta said:
can you explain why is that so, please?

The force on the spring should be the same throughout.
 
Like this i found it easy to do, thanks.

but isn't that the force for both springs combined?
I mean, you have the total displacement, and the Keff.

Or I can choose any of the springs, say F1 = Keff(x1+x2) ?
 
Last edited:
Fanta said:
Like this i found it easy to do, thanks.

but isn't that the force for both springs combined?
I mean, you have the total displacement, and the Keff.

Or I can choose any of the springs, say F1 = Keff(x1+x2) ?

You can choose any spring and it should work out.
 
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