- #1
jose1
- 2
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Hello
I have the exercise below:
Consider the function f(x)=1−8x2 on the interval [−5,6]. Find the average or mean slope of the function on this interval, i.e.
[f(6)-f(-5)]/[6-(-5)]
according to the theorem of laGrange
the slope in a continues function which is derivable in an interval should equal to f'(c), So
[f(6)-f(-5)]/[6-(-5)] is equal to 8. According to the site this is wrong?
and
f'(x) = -16x. So, -16x=8 is x=-1/2. According to the site this is wrong?
Could you please give me some advice? where is my mistake?
I will appreciate any help
Thanks
I have the exercise below:
Consider the function f(x)=1−8x2 on the interval [−5,6]. Find the average or mean slope of the function on this interval, i.e.
[f(6)-f(-5)]/[6-(-5)]
according to the theorem of laGrange
the slope in a continues function which is derivable in an interval should equal to f'(c), So
[f(6)-f(-5)]/[6-(-5)] is equal to 8. According to the site this is wrong?
and
f'(x) = -16x. So, -16x=8 is x=-1/2. According to the site this is wrong?
Could you please give me some advice? where is my mistake?
I will appreciate any help
Thanks