Find the derivative of a complicated expression

In summary, the question asks to find dP/dt of a given function. Using the product rule and the chain rule, the final derivative is 4096000t-3276800000(t^2)+5120-8192000-5120(e^-1600t).
  • #1
stau40
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Homework Statement


Find dP/dt of 2048000(t^2)(e^1600t)+5120t(e^-1600t)+3.2(e^-1600t)


Homework Equations





The Attempt at a Solution


2048000(2t(e^-1600t)-1600(t^2)(e^-1600t))+5120((e^-1600t)-1600(e^-1600t))+3.2(-1600(e^-1600t))
After moving the t over to simply the first part and multiplying thru I get:
4096000t-3276800000(t^2)+5120-8192000-5120(e^-1600t)

Can this be correct? For some reason it seems like I did something wrong, but I keep checking the numbers and can't figure out what it could be.

Thanks in advance!
 
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  • #2


The way you have presented your question is rather confusing so I am going to assume a function P(t) is equal to 2048000(t^2)(e^1600t)+5120t(e^-1600t)+3.2(e^-1600t). The trick to differentiating these kind of 'functions' is to really do it in parts, at least until you're comfortable using all the rules of differentiation. For example, try letting f(t) = 2048000(t^2), and g(t) = (e^1600t), then determine [f(t)g(t)]`. Next, let h(t) = 5120t, and p(t) = e^-1600t, then determine [h(t)p(t)]`. And of course, at last, take the derivative of the last term. So your derivative dP/dt = [f(t)g(t)]` + [h(t)p(t)]` + 3.2[e^-1600t]`. You can do this because the linearity of the derivative operation. At any rate, make sense?
 

FAQ: Find the derivative of a complicated expression

1. What is the definition of a derivative?

The derivative of a function at a specific point is the slope of the tangent line to the function at that point. It represents the rate of change of the function at that point.

2. How do you find the derivative of a complicated expression?

To find the derivative of a complicated expression, we use a set of rules and techniques called the chain rule, product rule, quotient rule, and power rule. We apply these rules systematically to simplify the expression and then take the derivative.

3. Why is finding the derivative important?

Finding the derivative allows us to understand the behavior of a function and its rate of change at a specific point. It is essential in many fields, including physics, economics, and engineering, as it helps us solve problems involving rates of change.

4. Can you give an example of finding the derivative of a complicated expression?

For example, if we have the expression f(x) = (x^2 + 2x)^3, we can use the power rule and chain rule to find the derivative. We first rewrite the expression as f(x) = (x^2 + 2x)^3 = u^3, where u = x^2 + 2x. Then, using the power rule, we get f'(x) = 3u^2 * u', where u' is the derivative of u. Finally, we apply the chain rule to find u', which is u' = 2x + 2. Therefore, the derivative of the original expression is f'(x) = 3(x^2 + 2x)^2 * (2x + 2).

5. Are there any tips for finding the derivative of a complicated expression?

Some tips for finding the derivative of a complicated expression include practicing the rules regularly, breaking down the expression into smaller parts, and using algebraic manipulations to simplify the expression before taking the derivative. It also helps to double-check your work and use a graphing calculator to visualize the function and its derivative.

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