- #1
chwala
Gold Member
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- Homework Statement
- see attached
- Relevant Equations
- Geometry
Text question is here and solution;
My approach;
##BP ×AP= PT^2##
Let ##AP= x##
Therefore, ##(6+x)x=16##
##x^2+6x-16=0##
##x=2## or##x=-8##
##⇒x=2## positive value only.
I guess this may be the only approach. Cheers!
My approach;
##BP ×AP= PT^2##
Let ##AP= x##
Therefore, ##(6+x)x=16##
##x^2+6x-16=0##
##x=2## or##x=-8##
##⇒x=2## positive value only.
I guess this may be the only approach. Cheers!