Find the magnitude of the velocity vector on impact

AI Thread Summary
To find the magnitude of the velocity vector on impact for Thelma and Louise's fall, the initial horizontal velocity is 25.9 m/s, and the vertical distance is 97 meters. The vertical final velocity can be calculated using the equation vf^2 = vi^2 + 2as, resulting in a final vertical velocity of -44.6 m/s. The horizontal velocity remains constant as air resistance is ignored. The overall impact velocity is determined by combining the horizontal and vertical components using the Pythagorean theorem. The final answer should be expressed to one decimal place without units.
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(resolved) find the magnitude of the velocity vector on impact

Thelma and Louise drive their '66 T-Bird convertible off a cliff. They are going 25.9 m/s and the cliff is 97 meters high. Find the magnitude of their velocity vector the moment they impact the ground. Make sure you do the following in your answer:

DO NOT include units. We'll deal with that in the next question.
Give precision to tenths (#.#).
Make your answer correct to within 0.2

so given y is -97, and vi is 25.9 m/s


equations for horizontal projectile motion for vf are
vyf=-g(t)
vf=sqrt of (vxf^2+vyf^2)
so far for t i had 4.447seconds

____
\/-2*-97
----------= 4.447
9.81
and had vyf as -44.6m/s
 
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You don't need the time.
You can use vf2 = vi2 + 2as for the vertical velocity
Since you ignore air resistance there is no change in the horizontal velocity.
 
And think of vxf and vyf as being two legs of a right triangle. The answer you're looking for is the hypotenuse of this triangle.
 
mgb_phys said:
You don't need the time.
You can use vf2 = vi2 + 2as for the vertical velocity
Since you ignore air resistance there is no change in the horizontal velocity.
what is 2as?
 
2 * acceleration * distance
It's one of the standard motion equations - although some books use different letters.
 
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