Find the Origin of the Kicked Soccer Ball

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AI Thread Summary
A soccer ball is kicked at 25 m/s at a 22-degree angle and strikes the crossbar at a height of 2.5 m. To find the origin of the kick, the velocity vector must be resolved into its x and y components. The positive y displacement of 2.5 m can be analyzed using the equation 2.5 = vy(t) + 0.5a(t^2), where vy is the initial vertical velocity and a is the acceleration due to gravity. Solving for time (t) using the quadratic formula is necessary, after which the distance traveled in the x-direction can be calculated with the equation distance = vx(t). This method allows for determining the initial position from which the soccer ball was kicked.
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Homework Statement



A soccer ball is kicked at 25 m/s at an angle of 22 degrees . The ball hits the crossbar 2.5 m off the ground. Where was it kicked from?

Homework Equations



d = ViT + .5* a * T^2

The Attempt at a Solution



I have no clue
 
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Resolve the velocity vector into components and work backwards from 2.5m in the y-direction.
 
So the soccer ball hits the crossbar (assuming it hits at 2.5 meters high). What does that mean? Do what fss said and break the motion into components, x and y. 2.5 is the positive y displacement. So we have 2.5 = vy (t) + 1/2a(t^2). So what is vy? and what is a? If you have a question about that, add a reply. So you should solve for t, using the quadratic formula. Then, in the x direction, you have distance (in the x-direction of course) = vx (t). So once you get t, you can plug in so you find the distance it traveled in the x-direction.
 
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