Find the ratio of the energy of the La characteristic x-ray to the Ka

ChrisWM
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Homework Statement
Find the ratio of the energy of the La characteristic x-ray to the Ka characteristic x-ray for: a) Potassium b) Copper
Relevant Equations
1/wavelength=R(z-1)^2*3/4
1/wavelength=R(z-7.4)^2*(1/4-1/n^2)
E=hc/wavelength
I found my energies for Potassium. I have 3.3 KeV for the k alpha nd 254.6 ev for L alpha, using z=19 and n=3. Are these values correct?
Edit: I found the ratio to be .077
 
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Your answers look correct to me.
 
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TSny said:
Your answers look correct to me.
Thanks!
 
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