Find the rotational inertia of a rod about a pivot

AI Thread Summary
To find the rotational inertia of a rod about a pivot located at L/3 from one end, the parallel-axis theorem can be applied. The rotational inertia when the pivot is at the center is (1/12)ML², and at the end, it is (1/3)ML². By using the parallel-axis theorem, the inertia can be calculated by adjusting for the distance from the center to the pivot point. This involves adding the product of the mass and the square of the distance from the center to the pivot. The discussion emphasizes the importance of understanding the parallel-axis theorem for solving this problem.
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Homework Statement



i need to find the rotational inertia of a rod about a pivot. The rod is of mass M and length L and is attached to a pivot of negligible friction located at a distance of L/3 from the left end of the rod.

Homework Equations





The Attempt at a Solution



i know that if the pivot were in the center it would be (1/12)ML and if the pivot were on the end it would be (1/3)ML, but i don't know how to find it at (L/3). can anyone help me? id really appreciate it! thanks.
 
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Try the parallel-axis theorem.
 
thanks, ill try it!
 
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