- #1
transgalactic
- 1,395
- 0
find the solution of this ln equation:
ax=lnx
i tried:
[tex]
e^{(ax)}=x
[/tex]
[tex]
e^{(ax)}-x=0
[/tex]
what to do next??
i thought of building a taylor series around 0 for ln
but ln(0) is undefined
??
ax=lnx
i tried:
[tex]
e^{(ax)}=x
[/tex]
[tex]
e^{(ax)}-x=0
[/tex]
what to do next??
i thought of building a taylor series around 0 for ln
but ln(0) is undefined
??
Last edited: