Find the threshold frequency for a calcium

AI Thread Summary
The discussion revolves around calculating the threshold frequency for calcium with a given work function of 3.33 eV. The correct formula used is f = W/h, where W is the work function converted to joules and h is Planck's constant. The user initially calculated the frequency as 8.04 x 10^14 Hz, but the book stated it was 5.02 x 10^14 Hz. After further examination, it was concluded that the book's answer was incorrect, confirming the user's calculation as accurate. This highlights the importance of verifying textbook answers in physics problems.
crimsondarkn
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Homework Statement



This is a pretty simple problem... Yet I got the wrong answer.. Hmm...

"Find the threshold frequency for a calcium surface whose work function is 3.33eV"

W=3.33eV = 3.33eV * 1.6x10^-19 J = 5.33x10^19 J
f = ?
h=6.63x10^-34 J*S

Homework Equations



f=W/h

The Attempt at a Solution



f=(3.33eV)(1.6x10^-19 J) / (6.63x10^-34 J*S) = 8.04x10^14 Hz <- My answerThe answer in book is 5.02 x10^14 Hz.

Can anyone tell me what I'm doing wrong?
 
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turns out the book was wrong... my answer was right. yah...
 
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