Find the velocity and strength of magnetic field from the given info

AI Thread Summary
To find the speed of the wire being pulled with a force of 1.30N, the power dissipated in the circuit is used to calculate the current, resulting in 3.75 amps. This current is then related to the electromotive force (ε) using the total resistance, yielding ε = 1.2 V. The equation ε = vBL is applied to find the speed of the wire, but the magnetic field strength remains unknown. The discussion highlights confusion around the relevance of the equation F = qvB, as the charge (q) is not provided. Ultimately, the focus is on using the established equations to derive both the speed of the wire and the strength of the magnetic field.
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Homework Statement



A 7.00-cm-long wire is pulled along a U-shaped conducting rail in a perpendicular magnetic field. The total resistance of the wire and rail is 0.320Ω . Pulling the wire with a force of 1.30N causes 4.50W of power to be dissipated in the circuit.

What is the speed of the wire when pulled with 1.30N ?

What is the strength of the magnetic field?

Homework Equations



ε=vBL
P=Fv
I=ε/R

I=sqrt(P/R)

The Attempt at a Solution



I=sqrt(P/R)

I=sqrt(4.5/0.32)=3.75 amps

I=ε/R

3.75 amps = ε/0.32

ε=1.2 V

ε=vBL

(1.2 V)=v(?)(0.07 m)

I'm not sure how to find the magnetic field, which I obviously need for both parts. Please help! Thanks!
 
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You wrote P = Fv as a relevant equation. Maybe it really is relevant. :wink:
 
Thanks!

But for the second part, I'm not sure of what to do.

F=qvB
1.3=q(3.46)B
But where does q come from?
 
The equation F = qvB is not relevant here. Now that you have a value for v, why not go back to your earlier equation ε = vBL?
 
Doh! Thanks a bunch!
 
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