Finding final velocity in a perfectly elastic collision

AI Thread Summary
In a perfectly elastic collision involving two equal mass marbles, marble A with an initial velocity of 1.69 m/s collides with marble B, which is initially at rest. After the collision, marble A comes to rest, leading to the question of marble B's final velocity. The conservation of momentum equation confirms that the final velocity of marble B is equal to the initial velocity of marble A, resulting in a final velocity of 1.69. The calculations are verified as correct, confirming that marble B's final velocity is indeed 1.69.
ilovedeathcab
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[solved] finding final velocity in a perfectly elastic collision

~~~Two marbles with equal masses collide. Marble A has an initial velocity of 1.69 m/s while marble B is initially at rest. If marble A comes to rest as a result of the initial collision, what is the final velocity of marble B?

* DO NOT include units in your answer.
* Give your answer with two decimals.
* Answers will be accepted if they are within 0.02 of the correct answer.

~Can anyone clarify this?
1. m1v1i + m2v2i = m1v1f + m2v2f

masses cancel...
2. v1i+v2i = v1f+v2f

3. (1.69m/s) + (0m/s) = (0m/s) + v2f

4. 1.69 m/s= v2f

I'm not sure this is correct...
 
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ilovedeathcab said:
~~~Two marbles with equal masses collide. Marble A has an initial velocity of 1.69 m/s while marble B is initially at rest. If marble A comes to rest as a result of the initial collision, what is the final velocity of marble B?

* DO NOT include units in your answer.
* Give your answer with two decimals.
* Answers will be accepted if they are within 0.02 of the correct answer.

~Can anyone clarify this?
1. m1v1i + m2v2i = m1v1f + m2v2f

masses cancel...
2. v1i+v2i = v1f+v2f

3. (1.69m/s) + (0m/s) = (0m/s) + v2f

4. 1.69 m/s= v2f

I'm not sure this is correct...

Looks correct.
 
thank you so much!
 
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