Finding potential using Greens function

AI Thread Summary
The discussion focuses on solving a potential problem using Neumann Green's function in cylindrical coordinates, addressing the equation ∇²φ = 0 with specific boundary conditions. The Green's function is derived, and its normal derivative is evaluated at the boundary surface. The potential on the z-axis is calculated under the condition of zero charge density, and the relationship with the boundary condition is examined. The participants discuss the need to expand the Green's function in terms of Bessel functions, although one contributor finds an alternative method. The thread emphasizes the importance of correctly handling the surface term in the potential calculation.
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Homework Statement


A potential ##\phi(\rho, \phi ,z)## satisfies ##\nabla^2 \phi=0## in the volume ##V={z\geqslant a}## with boundary condition ##\partial \phi / \partial n =F_{s}(\rho, \phi)## on the surface ##S={z=0}##.
a) write the Neumann Green's function ##G_N (x,x')## within V in cylindrical coordinates ##\rho, \phi, z (and \rho', \phi', z')##. Evaluate G and its normal derivative ##\partial G/ \partial n'## for x' on S.
b) For zero charge density and with boudnary condition ##F_S=E_0## (constant) within the circle ##\rho < a ## and zero outside, find the potential on the z-axis. compare the limit z-->0 of your solution with the given boundary condition.
c) Find the first two nonvanishing terms in the potential for ##r=\sqrt(\rho ^2 +z^2)>> a##. Compare with (b) where the two overlap. what is the charge inferred from the large-r potential?

Homework Equations



##\phi=<\phi>_S +\frac{1}{4 \pi \epsilon}\int \rho G_N d^3x' +\frac{1}{4 \pi} \int\frac{\partial \phi}{\partial \phi} G_N d^2a'##[/B]

The Attempt at a Solution


a) the green function is ##G_N = \frac{1}{|\vec x -\vec x'|}##
##|\vec x -\vec x'|^2 = \vec x.\vec x + \vec x'.\vec x' -2\vec x.\vec x' ##
thus in cyllindrical coordinates:
##G_N = \frac{1}{\sqrt (\rho^2 + z^2 +\rho'^2 + z'^2 -2\sqrt((\rho^2 + z^2)(\rho'^2 + z'^2)cos\gamma)}##
so its normal derivative for x' on S will vanish and its value for x' on S is (z'=0):
##G_N = \frac{1}{ (\rho^2 + z^2 +\rho'^2 -2\rho' \sqrt((\rho^2 + z^2)cos\gamma)^{1/2}}##

b) on the z axis ##\rho =0## (this is not the charge density ##\rho## from ## \nabla ^2 \phi=0## we know that charge density is zero that's why the volume term vanishes )and ##\theta=0 --> cos\gamma =cos\theta'## and on the sruface z'=0 ##cos\gamma=0##
##\phi=<\phi>_S +\frac{1}{4 \pi} \int E_0 \frac{1}{ (z^2 +\rho'^2 )^{1/2}} d^2a'##
as ##d^2a' = \rho' d\rho' d\phi'## we have the following

##\phi=<\phi>_S +\frac{E_0}{2} \int_{0}^{a} \frac{\rho' d\rho'}{ (z^2 +\rho'^2 )^{1/2}}##
I would like to ask if till this point I have done anything wrong or if I have missed anything? and also how should I proceed with the surface term: ##<\phi>_S##, since I don't know the value of ##\phi##. I appreciate any help. thank you for your time.
 
Last edited:
Fred Wright said:
You must expand your Green's function in terms of a sum over Bessel functions and modified Bessel functions. For a good explanation of this procedure see http://www.phys.lsu.edu/~jarrell/COURSES/ELECTRODYNAMICS/Chap3/chap3.pdf
I have actually found out a way to do it, its not through bessels functions though. but thank you for the help
 
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