Finding temperature change, thermodynamics first law

In summary, the conversation involved calculations using the PV=nRT equation to determine the final and initial pressures and temperatures. The final pressure was found to be 96629 and the initial pressure was 62639. However, there was a discrepancy with the temperatures, with an initial temperature of 81.79 and a final temperature of 167.747, resulting in a change of 85.957. The expert does not confirm the calculated pressures and questions the presence of a 1.5 factor in the ideal gas temperature calculation.
  • #1
JoeyBob
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Homework Statement
see attached
Relevant Equations
PV=nRT
So I calculated the final and initial pressures using the given eqns, ended up with the final pressure of 96629 and initial pressure of 62639.

Then I used the PV=nRT eqn to calculate the final and initial temperatures. T=P*V/(n*1.5*R).

I got an initial temperature of 81.79 and a final temperature of 167.747, which is a change in temperature of 85.957 but the answer is 122.74.
 
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  • #2
JoeyBob said:
Homework Statement:: see attached
Relevant Equations:: PV=nRT

So I calculated the final and initial pressures using the given eqns, ended up with the final pressure of 96629 and initial pressure of 62639.

Then I used the PV=nRT eqn to calculate the final and initial temperatures. T=P*V/(n*1.5*R).

I got an initial temperature of 81.79 and a final temperature of 167.747, which is a change in temperature of 85.957 but the answer is 122.74.
So, is there a problem statement somewhere involved here?
 
  • #3
Also, attaching units to your numbers would be helpful.
 
  • #4
Chestermiller said:
So, is there a problem statement somewhere involved here?

My bad. its attached to this reply
 

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  • #5
Your pressures are way off. Please redo the calculation.
 
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  • #6
I don't confirm either of the pressures you calculated. Also, what is that 1.5 factor doing in the denominator of your ideal gas temperature calculation?
 
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