Finding the equations of a graph

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The discussion focuses on finding the equations for a piecewise function representing a roller coaster track, specifically two parabolas that change at x = 15. One parabola opens downward and the other upward, both intersecting at the point (15, 12.25). Participants debate whether the graph represents parabolas or a cubic function, noting that a true parabola cannot change concavity. The lack of properly labeled axes and clarity in the graph complicates the equation derivation. Accurate identification of the vertex for both parabolas is essential for determining the equations.
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I am trying to do a College Algebra project and I am having difficulty findimg the two equations that make the piecewise function in the pictures below.

Letting y be the number of meters the track is above or below the ground
and x the number of meters horizontally from the high point, write the
equation/s expressing y in terms of x for the roller coaster track. The
parabola changes from turning down to turning up at x = 15.

ef47a3b5a9ab85de09af4efe115857fe5g.jpg
 
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Missionz12 said:
I am trying to do a College Algebra project by myself as my two partners are not available and I need to find the two equations that make the piecewise function in the pictures below.

Letting y be the number of meters the track is above or below the ground
and x the number of meters horizontally from the high point, write the
equation/s expressing y in terms of x for the roller coaster track. The
parabola changes from turning down to turning up at x = 15.
Are you given that it is a "parabola"? If so your graph can't possibly be right. A parabola is always concave upward or always concave downward.

If, instead, this might be cubic, which is what your graph looks like, then y= ax^3+ bx^2+ cx+ d and putting in four values for x and y gives you four linear equations to solve for a, b, c, d.

ef47a3b5a9ab85de09af4efe115857fe5g.jpg
 
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It is TWO different parabolas thus a piecewise function, One parabola opening downward and one opening upward. The downward opening parabola ends at (15,12.25) and the upward opening parabola starts at (15,12.25)
 
I believe that the problem is that the graph is badly drawn, If I could find the vertex of the two parabolas I could easily find the leading coefficient and have my equation in a matter of seconds, but the axis arent labeled properly nor is the line very well.
 
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