Finding the filtered output signal

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To find the filtered output signal y(t) for the given input signals using the causal LTI filter with the frequency response H(jω), several methods can be applied, including convolution, Fourier transform, and amplitude scaling. The graph indicates that H(jω) is a linear function, specifically H(jω) = -ω, which can be used to determine y(t) for each input signal. The discussion highlights the importance of selecting the appropriate method based on the nature of the input signal, with convolution being a common approach. Participants express confusion about the correct application of these methods and seek clarification on extracting H(jω) from the graph. Ultimately, understanding the relationship between the input signals and the filter's frequency response is crucial for accurately calculating y(t).
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A causal LTI filter has the frequency response H(jw) shown in the graph. For each of these input signals, determine the filtered output signal y(t).

1) x(t)=exp(jt)

2) x(t)=(sin(wt))u(t)

3) X(jw)= 1 / ((jw)(6+jw))

4) X(jw)= 1 / (2+jw)

I don't understand what I have to do to find y(t), any help is appreciated, thanks
 

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what is the function description of H(j \omega)? can you extract that out of the graph?
 
nothing much in the graph, just a straight line from (-1, 2j) to (1, -2j)
 
There are many ways to find y(t):
y(t) = h(t) * x(t) convolution
y(t) = F(H(jw)X(jw)) Fourier transform of Y(jw)
y(t) = H(jw)x(t) amplitude scaling if x is an eigenfunction

Which one is most applicable? Or which have you learned?
 
yes, i learned it before, so is it correct to say H(jw)= -w?
 
y"t" = h(t) * x(t)
y"t" = f(H(jw)X(jw)
y"t" = h(jw)x(t)
 
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