Finding where a function is sign definite, sign indefinite or sign semidefinite

  • #1
ChiralSuperfields
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Homework Statement
Please see below
Relevant Equations
Please see below
For this problem,
1716936186456.png

However, I'm confused how their got their solution. My solution is, using set builder notation,

##[ (x,y) \in \mathbf{R} : 1 - \cos x + y^4 ≥ 0 ]## which implies that ##V(0,0) = 0## so it satisfies the first condition for being sign definite, sign semidefinite, and sign indefinite. Then from the inequality, we know that for ##x \neq 0, y \neq 0## , then ##V(x,y) = 1 - \cos x + y^4 > 0## so their Liapunov satsifes the conditions for being positive definite. However, I'm confused by how they find the domain (they call it domain of attraction) from ##1 - \cos x + y^4 > 0##.

Does anybody please know how they do that?

Thanks!
 
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  • #2
What is the definition of sign definite/semi definite/indefinite?
 
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  • #3
If you are using a Liapunov function to find a domain of attraction for (I assume) a fixed point at [itex](0,0)[/itex], then you can't do that without reference to [itex](\dot x, \dot y)[/itex], and since you haven't given us that information we can't really help you.
 
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