- #1
ChiralSuperfields
- 1,331
- 142
- Homework Statement
- Please see below
- Relevant Equations
- Please see below
For this problem,
However, I'm confused how their got their solution. My solution is, using set builder notation,
##[ (x,y) \in \mathbf{R} : 1 - \cos x + y^4 ≥ 0 ]## which implies that ##V(0,0) = 0## so it satisfies the first condition for being sign definite, sign semidefinite, and sign indefinite. Then from the inequality, we know that for ##x \neq 0, y \neq 0## , then ##V(x,y) = 1 - \cos x + y^4 > 0## so their Liapunov satsifes the conditions for being positive definite. However, I'm confused by how they find the domain (they call it domain of attraction) from ##1 - \cos x + y^4 > 0##.
Does anybody please know how they do that?
Thanks!
However, I'm confused how their got their solution. My solution is, using set builder notation,
##[ (x,y) \in \mathbf{R} : 1 - \cos x + y^4 ≥ 0 ]## which implies that ##V(0,0) = 0## so it satisfies the first condition for being sign definite, sign semidefinite, and sign indefinite. Then from the inequality, we know that for ##x \neq 0, y \neq 0## , then ##V(x,y) = 1 - \cos x + y^4 > 0## so their Liapunov satsifes the conditions for being positive definite. However, I'm confused by how they find the domain (they call it domain of attraction) from ##1 - \cos x + y^4 > 0##.
Does anybody please know how they do that?
Thanks!