- #1
araz1
- 9
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Hi
Show that z-(1/z)=i2rsinx, given z=r(cosx+isinx)
Thanks.
Show that z-(1/z)=i2rsinx, given z=r(cosx+isinx)
Thanks.
Then it is not the case.araz said:No it is not z minus its conjugate. it is z minus (1 over z).
The formula for finding z-(1/z) is z=r(cosx+isinx) - 1/z.
To find the value of z, you need to know the values of r, cosx, and sinx, and then plug them into the formula z=r(cosx+isinx) - 1/z.
Z-(1/z) is a complex number that is obtained by subtracting the reciprocal of z from z. It is a common operation in complex number arithmetic and is used in various applications in mathematics and engineering.
Finding z-(1/z) can help in simplifying complex expressions and solving equations involving complex numbers. It is also used in analyzing circuits, signal processing, and other mathematical and scientific fields.
Yes, there are a few special cases to consider, such as when z=0 or when the value of z is purely real or purely imaginary. In these cases, the formula for z-(1/z) may need to be modified or the result may be undefined.