Fixed charge inside a metallic sphere

  • Thread starter Thread starter student85
  • Start date Start date
  • Tags Tags
    Charge Sphere
AI Thread Summary
The discussion centers on the effects of a metallic sphere on the forces acting on charged particles, specifically comparing a charge inside the sphere to one outside. Gauss' law indicates that the electric field inside a conducting sphere is zero, meaning no force acts on a charge within it. However, if the sphere is uncharged, the electric field of a charge inside remains unaffected by the sphere. If the sphere is charged, the resultant electric field is determined by the vector sum of the fields from both the sphere and the point charge. The interaction of charges and the properties of the sphere significantly influence the forces experienced by the charges.
student85
138
0
There is a question someone asked me and I'm not sure about the answer:
Suppose you have two identical positive, fixed in position, charged particles. One of them is inside a metallic sphere with air inside it, so it's more like an empty shell. What will be the force acting on the particle inside the sphere in comparison to the one outside it? Are there any differences? Does the sphere affect anything?
 
Physics news on Phys.org
Gauss' law tells us that the electric field inside a sphere is zero. The electric field outside sphere is the same as the field of the [net] charge of Q.

Do you know why the force is zero inside a sphere? Mayb of you work out an example yourself, it may become clear. Just choose any point in the sphere and call it Q, if you apply some geometry to the situation, I'm sure you can figure out why forces cancel out.
 
Even if there is a charge inside the sphere, you're telling me there is no charge inside the sphere?
I really don't think that. Take your gaussian surface as a sphere smaller than the actual metallic sphere and clearly there is a charge inside it.
So could someone please answer my question, please read it carefully.
 
ranger said:
Gauss' law tells us that the electric field inside a sphere is zero.
This is true for a charged conducting spherical shell, but is not true for a point charge placed inside a spherical shell.
student85 said:
There is a question someone asked me and I'm not sure about the answer:
Suppose you have two identical positive, fixed in position, charged particles. One of them is inside a metallic sphere with air inside it, so it's more like an empty shell. What will be the force acting on the particle inside the sphere in comparison to the one outside it? Are there any differences? Does the sphere affect anything?
That depends. If your spherical shell in uncharged then the electric field of the point charge will not be perturbed; i.e. the electric field of either point charge will be unaffected. However, if your spherical shell is charged, then you can find the resultant electric field by finding the vector sum of the electric field from the spherical shell and the point charge(s).
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up will act downwards and maximum static friction will act downwards Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top