- #1
tomz
- 35
- 0
Dear all
I am having a problem on circular flow of fluid. On all books I have read they say
[itex]\frac{dp}{dr}[/itex]=[itex]\rho[/itex]v[itex]^{2}[/itex][itex]/r[/itex]
Which make sense by using infinitesimal square volume and take the force exert.
But if I use a circular infinitesimal volume (which is usually the case for circular things), i get a different answer because the side with greater pressure have greater area.
Why is this ?
Thank you
I am having a problem on circular flow of fluid. On all books I have read they say
[itex]\frac{dp}{dr}[/itex]=[itex]\rho[/itex]v[itex]^{2}[/itex][itex]/r[/itex]
Which make sense by using infinitesimal square volume and take the force exert.
But if I use a circular infinitesimal volume (which is usually the case for circular things), i get a different answer because the side with greater pressure have greater area.
Why is this ?
Thank you