- #1
xc630
- 13
- 0
Hello i am having toruble with this problem.
A 24 kg block is pushed along a horizontal surface with an acceleration of 2.0 m/s^2. The coeficient of friction is 0.25 and teh block starts at 1.0m/s. Find: the force being applied horizontally, the velocity after 5.0 s, and the distance moved in 5.0 s.
I drew a force diagram by the way too.
Since the velocity is not constant
I have these premises: x-axis is accelerated and the y- axis is at rest so it is at equilibrium so sigmaF=0
Thus I have
sigmaF= ma Sigmaup= sigma down
Sigma Fx = Fa(force applied) - f (friction) N(normal force)= Fw
Sigma Fx= Fa- uN N= Fw(f=uN)
What should I do next to find Fa the applied force? Thanks for any help
I don't know what to
A 24 kg block is pushed along a horizontal surface with an acceleration of 2.0 m/s^2. The coeficient of friction is 0.25 and teh block starts at 1.0m/s. Find: the force being applied horizontally, the velocity after 5.0 s, and the distance moved in 5.0 s.
I drew a force diagram by the way too.
Since the velocity is not constant
I have these premises: x-axis is accelerated and the y- axis is at rest so it is at equilibrium so sigmaF=0
Thus I have
sigmaF= ma Sigmaup= sigma down
Sigma Fx = Fa(force applied) - f (friction) N(normal force)= Fw
Sigma Fx= Fa- uN N= Fw(f=uN)
What should I do next to find Fa the applied force? Thanks for any help
I don't know what to