Force on Planet Moving in Interstellar Dust

AI Thread Summary
The discussion revolves around calculating the retarding force on a planet moving through interstellar dust. The participant initially derived a formula for the effective radius of dust interaction using conservation laws but faced confusion regarding the assumptions made about speed and momentum conservation. They clarified that the planet's motion is uniform and not orbital, emphasizing that the dust's flow rate into the planet may be the source of error. Questions were raised about the correctness of the derived radius and the assumption of constant speed, suggesting that a more nuanced understanding of momentum conservation is necessary. The conversation highlights the complexity of the problem and the need for careful consideration of physical principles in the calculations.
BigD
Messages
14
Reaction score
0

Homework Statement



A uniform, spherical planet of mass M and radius R moves SLOWLY with an essentially uniform speed v through a cloud of interstellar dust particles, whose density is ρ. The dust particles are attracted towards the planet, and some of them would eventually fall onto its surface.

Find the resulting retarding force on the planet due to the dust cloud.
Since the planet moves slowly, initial speed and final speed can be assumed to be the same.


Homework Equations



Angular momentum => Li = Lf
Momentum => Pi = Pf
Energy including
Potential energy = -GMm/R
Kinetic Energy = 1/2 (mv2)


The Attempt at a Solution



I assumed the planet would consume all the dust within a circular cross section. By using conservation of energy and angular momentum, I got the radius of this circle to be

R' = (R^2 + 2RGM/v^2)^1/2

Then I used

dm = ρAdx = ρ(πR'^2)dx

to get

F = dp/dt = (dm/dt)v = ρπR^2(v^2 + 2GM/R).

I was told this wasn't right. Can someone give me a hint as to what I did wrong?
 
Physics news on Phys.org
Why did you put the planet in orbit? Per the problem statement it is moving with an "essentially uniform velocity". No mention of an orbit.
 
D H said:
Why did you put the planet in orbit? Per the problem statement it is moving with an "essentially uniform velocity". No mention of an orbit.

I didn't.
 
The circle I mentioned was not an orbit; it was the cross section swept out by the planet.

I could really use some help on this.
 
A couple of questions.

1. How did you derive that R' = (R^2 + 2RGM/v^2)^1/2 ?

2. Are you sure that the statement 'initial speed and final speed can be assumed to be the same.' is correct? This doesn't make a bit of sense. It means that momentum is not conserved. Better would be to assume that the initial and final speeds are approximately the same. (In other words, you can ignore second-order effects.)
 
D H said:
A couple of questions.

1. How did you derive that R' = (R^2 + 2RGM/v^2)^1/2 ?

2. Are you sure that the statement 'initial speed and final speed can be assumed to be the same.' is correct? This doesn't make a bit of sense. It means that momentum is not conserved. Better would be to assume that the initial and final speeds are approximately the same. (In other words, you can ignore second-order effects.)

1. I started by changing the frame of reference to the planets center of mass so that the dust moves at speed v. I assumed that at some perpendicular distance R' from the trajectory of the planet the dust particles would just barely miss the planet and that they would pass at the radius of the planet R with some velocity v' perpendicular to the radius vector. I used conservation of energy and angular momentum to solve for R' in

Rv' = R'v
(1/2)v^2 = (1/2)v'^2 - GM/R

I think this part of the problem is right because I got the same result from another method. I'm guessing I did something wrong in the rate at which the dust flows into the planet.

2. I'm sure that it's right. I assume it means that the force that we want to find is negligable compared with the planet's momentum.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Correct statement about a reservoir with an outlet pipe'
The answer to this question is statements (ii) and (iv) are correct. (i) This is FALSE because the speed of water in the tap is greater than speed at the water surface (ii) I don't even understand this statement. What does the "seal" part have to do with water flowing out? Won't the water still flow out through the tap until the tank is empty whether the reservoir is sealed or not? (iii) In my opinion, this statement would be correct. Increasing the gravitational potential energy of the...
Back
Top