Forced oscillation (mass & spring)

AI Thread Summary
A 2 kg object attached to a frictionless spring is driven by an external force F = (3.00N)sin(2πt), with a spring constant of 20.0 N/m. The amplitude of the motion can be calculated using the equation A = (F0/m)/√(w² - w0²), where w is the driving frequency and w0 is the natural frequency. The correct natural frequency w0 is √(k/m), which equals 10 in this scenario. After correcting the value for w0, the amplitude calculation yields the book's answer of 5.09 cm. Proper application of these principles leads to the correct solution.
kash25
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Homework Statement


A 2 kg object attached to a spring moves without friction and is driven by an external force given by F = (3.00N)sin(2\pit). The force constant of the spring is 20.0N/m.
Find the amplitude of the motion.


Homework Equations


I am not sure but I am trying to use:
A = (F0/m)/\sqrt{}(w^2-w<sub>0</sub>^2)^2


The Attempt at a Solution


Applying this equation using w equals 2pi and w0 is k/m (10) gives an amplitude of 0.00173. The solution in the book says 5.09cm.
Am I approaching this question correctly?
 
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Hi kash25,
kash25 said:

Homework Statement


A 2 kg object attached to a spring moves without friction and is driven by an external force given by F = (3.00N)sin(2\pit). The force constant of the spring is 20.0N/m.
Find the amplitude of the motion.


Homework Equations


I am not sure but I am trying to use:
A = (F0/m)/\sqrt{}(w^2-w<sub>0</sub>^2)^2


The Attempt at a Solution


Applying this equation using w equals 2pi and w0 is k/m (10)

w0 is not equal to k/m. If you correct this you should get the right answer.
 
Not exactly sure...but that equation you have might be for forced oscillations working against friction; in this case there is no friction.
 
Gear300 said:
Not exactly sure...but that equation you have might be for forced oscillations working against friction; in this case there is no friction.

No, it's the right equation. If it was a damped spring there would be another term under the radical. Using that equation (with the corrected value for w0) gives the answer given in the post.
 
remember that w0 = sqrt (k/m).

That will give you the right answer :)
 
stupid mistake..thanks for your help!
 
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