Free Fall and gravitational acceleration

AI Thread Summary
A ball dropped from a height of 1.5 meters takes 0.54 seconds to hit the ground, prompting a calculation of gravitational acceleration (g). The equation used is y = 1/2gt^2, leading to an initial calculation of g as approximately 10.27 m/s². However, the correct value, calculated with more precision, is 10.29 m/s². The discrepancy from the accepted value of 9.8 m/s² highlights the importance of accuracy in calculations. The discussion concludes with an acknowledgment of understanding the correct approach.
tgilli
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Homework Statement



A ball is dropped from 1.5 y(m) and hits the ground in .54 t(s). What is the value of g (m/s^2)?

The accepted value of g = 9.8m/s^2


Homework Equations


y=1/2gt^2


The Attempt at a Solution



I'm getting this wrong, but this is my attempt.

1.5 = 1/2g x .54^2
1.5 = 1/2 x .292
1.5 = .146
.146 / 1.5 =

10.27 g (m/s^2)

10.27 g (m/s^2) is close, but not correct. The correct answer is 10.29 m/s^2

Clarification would be appreciated.
 
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tgilli said:

Homework Statement



A ball is dropped from 1.5 y(m) and hits the ground in .54 t(s). What is the value of g (m/s^2)?

The accepted value of g = 9.8m/s^2


Homework Equations


y=1/2gt^2


The Attempt at a Solution



I'm getting this wrong, but this is my attempt.

1.5 = 1/2g x .54^2
1.5 = 1/2 x .292
1.5 = .146
.146 / 1.5 =

10.27 g (m/s^2)

10.27 g (m/s^2) is close, but not correct. The correct answer is 10.29 m/s^2

Clarification would be appreciated.

Calculate the expression with more precision. I get 10.288
 
LowlyPion said:
Calculate the expression with more precision. I get 10.288


Got it and understand. Thanks.
 
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