Free fall equations Sky diver Felix need some help please

AI Thread Summary
The discussion revolves around calculating the free fall equations for skydiver Felix Baumgartner, specifically to determine the time and distance he would take to reach the speed of sound. The user initially neglected air resistance but found the results unreasonable, leading to the inclusion of a drag coefficient. They provided specific values for Felix's weight and altitude but ended up with implausible results, such as a time of 2.7 x 10^56 seconds and a velocity of 53 m/s. The user seeks assistance in correcting their calculations and understanding where they went wrong. The conversation highlights the complexities of free fall physics, especially when factoring in air resistance.
najat
Messages
10
Reaction score
0
free fall equations ...Sky diver Felix :) need some help please

hi :)

OK..i tried to use the equations below to evaluate the distance or the time at which felix will reach the speed of sound ...but i failed ..i need some help:
here what i did:

first i neglect the air resistance , but the result was unreasonable so i used these:

jb13498311781.jpg


i assumed that :

m=weight of felix=70 kg
h=the height=36000 m
k=air resistance=0.24 >> i think "k" during the falling and by the time will be increased to 70

the result was :
t=2.7*10^56 sec :0
v=53 m/s :(

i don't know what i miss here ! so if someone will help me i will be so tankful ..
 
Physics news on Phys.org


hi ..
any body have any idea :(

by the way this is not for home work , it just a question pop up to me and i want to solve it , but it has been moved here :)
 


Just for info...

http://hypertextbook.com/facts/JianHuang.shtml

"An hour and thirty-one minutes after launch, my pressure altimeter halts at 103,300 feet. At ground control the radar altimeters also have stopped-on readings of 102,800 feet, the figure that we later agree upon as the more reliable. It is 7 o'clock in the morning, and I have reached float altitude …. Though my stabilization chute opens at 96,000 feet, I accelerate for 6,000 feet more before hitting a peak of 614 miles an hour, nine-tenths the speed of sound at my altitude."

Scroll down that page for the maths.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top