Frequency and other properties from E-field

AI Thread Summary
The discussion revolves around solving a physics problem related to a plane, harmonic, linearly polarized light wave described by a specific electric field intensity equation. Participants express confusion about the cosine argument and the relationship between angular frequency, frequency, wavelength, and the index of refraction of glass. Key points include the identification of angular frequency and wave number, with clarifications provided on the calculations for frequency and velocity of the wave. The correct interpretation of the equation is confirmed, emphasizing that there is no additional factor of two in front of pi. The conversation highlights the importance of understanding wave properties and the mathematical manipulation required to solve the problem.
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Homework Statement



A plane, harmonic, linearly polarized light wave has an electric field intensity given by
{E}_z = {E}_0 cos pi*10^{15}*(t - x/.65c)

while traveling in a piece of glass. Find
(a) The frequency of the light.
(b) Its wavelength.
(c) The index of refraction of the glass.

The Attempt at a Solution



I'm still confused about the argument of the cosine, but I assume that what was within the parenthesis was the real argument. Under this assumption, it fits the form (kx-wt) with some tweaking. The angular frequency w will give me the frequency. I'm pretty sure I need the velocity in order to get the wavelength, and am unsure as to how to find it. Once I get the velocity it will be easy to find the index of refraction.

The problems I ran into:
w=-1 in this case, and so 1/2pi gives me the frequency.
finding velocity of the wave: I used w^{2}/k^{2} = v, however this gives me a value much larger than the speed of light.

Should I just distribute the stuff before the argument? I've never seen a cosine like that. I think that it would be better if it was cos(pi*10^15*(t-x/.65c)) and am confused as to why they didn't do that if that is really what they meant.

Thanks for any help you can provide!
 
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Is there a 2 in front of th e"pi" in the formula?

The wave is in the form
E_z=E_0 cos(\omega t -kx) =E_0 cos(2\pi f t -\frac{2\pi}{\lambda}x) =
=E_0 \cos2\pi f ( t -\frac{x}{v})
where I used
\omega=2\pi f, k=\frac{2\pi}{\lambda}, \lambda=c/f
So v=0.6 c, f=10^15 Hz
 
Last edited:
nasu said:
Is there a 2 in front of th e"pi" in the formula?

Nope, it's just pi. Thank you so much! I didn't know what k equaled. Thanksthanksthanks.
 
Then 2f =10^15.
 
nasu said:
Is there a 2 in front of th e"pi" in the formula?

The wave is in the form
E_z=E_0 cos(\omega t -kx) =E_0 cos(2\pi f t -\frac{2\pi}{\lambda}x) =
=E_0 \cos2\pi f ( t -\frac{x}{v})
where I used
\omega=2\pi f, k=\frac{2\pi}{\lambda}, \lambda=c/f
So v=0.6 c, f=10^15 Hz

Please do not post solutions to homework questions.
 
Sorry if I posted more that I was supposed to.
I am aware that the forum policy requires that the poster shows some work and ideas.
I considered that in this case he showed some start and he is only confused about the math manipulation of the formula.
I'll be more careful in the future.
 
What is K and lambda, can anyone explain please
 
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