Frequency for Vibration Modes of a Square Membrane

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The frequency of vibration modes for a square membrane can be calculated using the equation ω m,n = ∏ [(m/a)^2 + (n/b)^2]^(1/2). For modes (2,1) and (1,2) on a square plate, these frequencies are equal, and their linear combinations also yield modes at the same frequency. In contrast, for a rectangular plate where a ≠ b, the frequencies differ, and combinations like (2,1)+(1,2) do not exist. The discussion clarifies that in a square plate, any linear combination of modes with the same frequency results in a mode that retains that frequency. Thus, the relationship between the modes and their frequencies is consistent in square membranes.
Johnny122
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So the equation to obtain the frequency of the modes of a square membrane is something like

ω m,n = ∏ [(m/a)^2 + (n/b)^2]^(1/2)

This equation can be used to get the frequency for Modes such as (2,1) and (1,2). How do I get the frequency for such modes as (2,1)+(1,2) and (2,1)-(1,2) ? Picture attached shows the modes.
 

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If it is a square plate, the frequencies for (2,1) and (1,2) are the same, and the others in your picture are linear combinations of them, also at the same frequency.

For a rectangular plate with ##a \ne b##, the (2,1) and (1,2) frequencies are different and the "(2,1)+(1,2) and (2,1)-(1,2) modes" don't exist.
 
Let's say that the frequency for (2,1) = x and (1,2) = y , so by linear combination, do you mean something like a x + b y = z where a and b are constants? And z would be the frequency for (2+1)+(1,2) or (2-1)-(1,2) ?
 
Johnny122 said:
Let's say that the frequency for (2,1) = x and (1,2) = y

It's a square plate, so a = b in your formula for the frequencies. So x = y.

In any structure that has two (or more) modes with the same frequency, and combination of the modes is also a "mode" with the same frequency.
 
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