- #1
zpt3593
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A block is projected up an incline making an angle theta with the horizontal. It returns to its initial position with half its initial speed.
I have absolutely no idea how to do this problem. I would think i would have to use the equation x = x +v(t) + (1/2)at^2 or maybe the equation x= (v^2) / (2ug)
I have absolutely no idea how to do this problem. I would think i would have to use the equation x = x +v(t) + (1/2)at^2 or maybe the equation x= (v^2) / (2ug)