Gauss' Law: Net Electric Field of Two Spheres

AI Thread Summary
The discussion centers on calculating the net electric field at x=2.0 cm due to two nonconducting spheres with given surface charge densities. It is established that the electric field inside a uniformly charged sphere is zero, but the influence of the second sphere must be considered since they are nonconducting. The participant confirms that the electric field due to the first sphere at that point is zero, while the second sphere's effect is treated as if all its charge were concentrated at its center. The final calculation yields a net electric field of -3.10 x 10^3 N/C, indicating the direction of the field. This confirms the importance of considering both spheres in the analysis of the electric field.
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Homework Statement


Two nonconducting spheres, of r1=3.0cm and r2=2.0cm, are placed of an x-axis. They have surface charge densities of +6.0mC/m2 and +4.0 mC/m2, respectively, on their outside surfaces. The center of sphere r1 is on the origin and the center of sphere r2 is 10 cm away. What is the net electric field at x=2.0 cm?



Homework Equations


E=kq/r2
Area=4pir2

The Attempt at a Solution


I noticed that x=2.0cm falls inside sphere r1 and that the Electric Field inside a sphere due to an outside charge equals 0. I think this is the answer but want to be sure.
 
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I do not think so! because they are non conducting spheres... so we can not ignore the effect of the second sphere, I guess! i will look it up more though...
 
The field inside a uniformly charged sphere is zero (the field of THIS sphere vanishes), but the field outside a uniformly charged sphere is the same as if all the charge was at its center (we can treat it like a point-charge on most regards)... You should get your answer easily!
 
Yeah I tried that before you told me and it was pretty easy and good to know the way i thought was right. I got -3.10x10^3 N/C because of the direction of the field
 
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