General and Special Relativity Minkowski spaces

AI Thread Summary
The discussion focuses on solving homework problems related to General and Special Relativity, specifically regarding Minkowski spaces and metric tensors. Participants clarify the representation of the metric as a matrix and confirm that the components of the metric tensor are constant, leading to zero Christoffel symbols. This implies simplifications in deriving geodesic equations, as the absence of Christoffel symbols indicates straight-line motion in spacetime. The conversation emphasizes the importance of understanding the relationships between metric components and their derivatives in the context of relativity. Overall, the thread highlights the challenges and methodologies in tackling complex problems in relativity coursework.
kikitard
Messages
5
Reaction score
0

Homework Statement


In attached image

Homework Equations


?

The Attempt at a Solution


?

A start would be fantastic!
 

Attachments

  • Screen shot 2013-03-05 at 10.51.23 PM.png
    Screen shot 2013-03-05 at 10.51.23 PM.png
    14.9 KB · Views: 589
Physics news on Phys.org
If you don't have ANY idea how to start ANY of these you might be in the wrong course. 3(a) just wants you describe the metric as a matrix. If (dt,dx,dy) is the vector ##dx^\mu## what matrix ##g_{\mu \nu}## makes ##dx^\mu dx^\nu g_{\mu \nu}## equal to the metric expression?
 
I'm pretty sure I am in the wrong course, but it is required, which is why I've turned to the internet for help.

Am I correct in saying that the dxν = transpose of dxμ, and so gμν is the matrix with row vectors (-1,0,0) (0,1,0) (0,0,1), or am I off base?
 
kikitard said:
I'm pretty sure I am in the wrong course, but it is required, which is why I've turned to the internet for help.

Am I correct in saying that the dxν = transpose of dxμ, and so gμν is the matrix with row vectors (-1,0,0) (0,1,0) (0,0,1), or am I off base?

That's a good start. Absolutely right. Now try 3(b).
 
Using this formula (attached) can i retain the β in the formula, giving 1/2g\mu\beta((∂gβ\alpha/∂xβ)+(∂gββ/∂x\alpha)-(∂g\alpha\beta/∂xβ))

we know gab=gba so the first and third terms in the brackets cancel
giving 1/2g\mu\beta(∂gββ/∂x\alpha)
?
Would the partial derivative wrt xalpha be 0, as there are no xalpha terms contained in gββ?
 

Attachments

  • Screen shot 2013-03-06 at 12.01.56 AM.png
    Screen shot 2013-03-06 at 12.01.56 AM.png
    3.9 KB · Views: 499
kikitard said:
Using this formula (attached) can i retain the β in the formula, giving 1/2g\mu\beta((∂gβ\alpha/∂xβ)+(∂gββ/∂x\alpha)-(∂g\alpha\beta/∂xβ))

we know gab=gba so the first and third terms in the brackets cancel
giving 1/2g\mu\beta(∂gββ/∂x\alpha)
?
Would the partial derivative wrt xalpha be 0, as there are no xalpha terms contained in gββ?

That's hard to read. But all of the metric components are constant. So all of the partial derivatives of the metric are zero. So the Christoffel symbols are?
 
Dick said:
That's hard to read. But all of the metric components are constant. So all of the partial derivatives of the metric are zero. So the Christoffel symbols are?

Ahh that makes sense, all partial derivatives are zero, so the Christoffel is also zero.

for c) I managed to get the attached image as the geodesic with affine λ
in d) i must solve this (presuming i did it correctly), could you point me towards the right method?
 

Attachments

  • Screen shot 2013-03-06 at 12.46.19 AM.png
    Screen shot 2013-03-06 at 12.46.19 AM.png
    2 KB · Views: 494
for c) You derived the geodesic equation in general it looks like. You got the right answer for that, but you can also try to find the specific case geodesic equation.

Regardless, in part b) you found that the christoffel symbol was zero. What does that imply about your answer to part c)? Does that give you something easy to solve for part d)?
 
Back
Top