- #36
NoahsArk
Gold Member
- 258
- 24
Because of the very good responses here, I have a better understanding of how relativity of simultaneity works. If clocks are lined up inside a rocket side by side in a row, like a row of seats, and there are several rows of clocks going from the back to the front of the rocket, then the clocks in any particular row will be synchronized in the stationary frame as well as in the rocket's frame. However, clocks belonging to different rows will not be synchronized according to the stationary frame. Also, all clocks in the rocket, no matter what row they are in, will be ticking at the same rate, its just that the different rows won't be synchronized in the stationary frame.
The why part of this I still don't understand. In the example with the rows of clocks, none of the clocks have any motion relative to the rocket. In all the examples that I've seen about relativity of simultaneity ("R.O.S"), there is motion of the clock relative to the rocket- either in the same direction that the rocket is moving or in the opposite direction. Here are two contrasting examples, both of which should involve R.O.S, but only the first example makes sense to me as to why it's occurring. The first example is a little repetitive, but I need to use it to contrast with the second:
1) From the middle of the rocket, two beams of light shoot out towards opposite ends of the rocket. Someone inside the rocket will observe the two beams hitting the opposite ends simultaneously. Someone in the rest frame will observe the beam hitting the back end first. This makes sense because the person in the middle of the rocket sees both beams traveling an equal distance at speed C. The person in the rest frame sees the beam traveling a longer distance to get to the front of the rocket. Given that C is constant, it's logical that the stationary observer will see the beam hitting the back end (which involves shorter travel), sooner than the front end.
2) A rocket is moving while two events happen at the back and front of the rocket simultaneously from the rocket frame. Say the event is just a flash of light where, unlike in example one above, there is no movement toward either end of the rocket (for example, if two people, one in the back and one in the front, both had a flash light pointing upwards, and they each turned the flash light on and off). In this example, we could also use, instead of a flash light, a ball being dropped on both ends, or two people clapping their hands on both ends, etc. From the stationary observer's point of view, the event that happened in the back of the rocket did not involve any extra distance of travel compared to the event in the front. This is in contrast to the beams of light in the first example where the only reason R.O.S. occurred was due to the different distances that had to be traveled before the first event (the beam hitting the back) and the second event (the beam hitting the front) could occur.
Am I missing something fundamental?
The why part of this I still don't understand. In the example with the rows of clocks, none of the clocks have any motion relative to the rocket. In all the examples that I've seen about relativity of simultaneity ("R.O.S"), there is motion of the clock relative to the rocket- either in the same direction that the rocket is moving or in the opposite direction. Here are two contrasting examples, both of which should involve R.O.S, but only the first example makes sense to me as to why it's occurring. The first example is a little repetitive, but I need to use it to contrast with the second:
1) From the middle of the rocket, two beams of light shoot out towards opposite ends of the rocket. Someone inside the rocket will observe the two beams hitting the opposite ends simultaneously. Someone in the rest frame will observe the beam hitting the back end first. This makes sense because the person in the middle of the rocket sees both beams traveling an equal distance at speed C. The person in the rest frame sees the beam traveling a longer distance to get to the front of the rocket. Given that C is constant, it's logical that the stationary observer will see the beam hitting the back end (which involves shorter travel), sooner than the front end.
2) A rocket is moving while two events happen at the back and front of the rocket simultaneously from the rocket frame. Say the event is just a flash of light where, unlike in example one above, there is no movement toward either end of the rocket (for example, if two people, one in the back and one in the front, both had a flash light pointing upwards, and they each turned the flash light on and off). In this example, we could also use, instead of a flash light, a ball being dropped on both ends, or two people clapping their hands on both ends, etc. From the stationary observer's point of view, the event that happened in the back of the rocket did not involve any extra distance of travel compared to the event in the front. This is in contrast to the beams of light in the first example where the only reason R.O.S. occurred was due to the different distances that had to be traveled before the first event (the beam hitting the back) and the second event (the beam hitting the front) could occur.
Am I missing something fundamental?