MHB Geocaching: Solve a+b=c c/b=b/a Problem

  • Thread starter Thread starter TheCricketer
  • Start date Start date
AI Thread Summary
The discussion revolves around solving a mathematical problem related to geocaching, specifically finding the distance of AB given the proportions of AC:BC and BC:AB. The equations c = a + b and c/b = b/a are established as foundational relationships. Participants express confusion over the calculations and seek simplified formulas, particularly for variable b. The Quadratic Formula is mentioned as a method for deriving solutions, emphasizing the importance of demonstrating mathematical processes. Ultimately, the conversation highlights the challenge of determining specific distances without actual values, focusing instead on the relationships between the variables.
TheCricketer
Messages
2
Reaction score
0
I love geocaching and a problem that recently came up is:

A--------------B------------C (not to scale)

Find the distance of AB if the proportion of AC:BC is equal to BC:AB. Substituting a for AB, b for BC and c for AC, I come up with:

a+b=c where c/b=b/a

I'm at a loss here. When I put it in WA it comes up with the answer (although looking at the answer, I have no idea how it calculated it) and I was able to "brute force" my answer as well and get the right answer (thanks Excel) but I want to know the math behind it. The actual values are irrelevant as I want to get to the simplified formulas.
 
Mathematics news on Phys.org
Surely, you realize that you can't determine the actual distance from A to B knowing only proportions?

What, exactly, did you put into WA?
 
You have relationships. Without actual values, that's all you have.

c = a+b -- good

c/b = b/a -- good

You could also write $\dfrac{a+b}{b} = \dfrac{b}{a}$

You could also write $a^{2}+ab = b^{2}$

You could also write $(a-b)^{2} = ab$

You could also write: $a = \dfrac{b}{2}(\sqrt{5}-1)$

Which simplified formulas would you like?
 
tkhunny said:
You have relationships. Without actual values, that's all you have.

c = a+b -- good

c/b = b/a -- good

You could also write $\dfrac{a+b}{b} = \dfrac{b}{a}$

You could also write $a^{2}+ab = b^{2}$

You could also write $(a-b)^{2} = ab$

You could also write: $a = \dfrac{b}{2}(\sqrt{5}-1)$

Which simplified formulas would you like?

Can you simplify for b please and show the work? I don’t know where the $\sqrt{5}$ comes from.
 
TheCricketer said:
Can you simplify for b please and show the work? I don’t know where the $\sqrt{5}$ comes from.

This is where you get to demonstrate your love of mathematics. I used the Quadratic Formula with the expression immediately above. There are a few other ways to do it. Show your work!
 
Fermat's Last Theorem has long been one of the most famous mathematical problems, and is now one of the most famous theorems. It simply states that the equation $$ a^n+b^n=c^n $$ has no solutions with positive integers if ##n>2.## It was named after Pierre de Fermat (1607-1665). The problem itself stems from the book Arithmetica by Diophantus of Alexandria. It gained popularity because Fermat noted in his copy "Cubum autem in duos cubos, aut quadratoquadratum in duos quadratoquadratos, et...
Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...
Thread 'Imaginary Pythagorus'
I posted this in the Lame Math thread, but it's got me thinking. Is there any validity to this? Or is it really just a mathematical trick? Naively, I see that i2 + plus 12 does equal zero2. But does this have a meaning? I know one can treat the imaginary number line as just another axis like the reals, but does that mean this does represent a triangle in the complex plane with a hypotenuse of length zero? Ibix offered a rendering of the diagram using what I assume is matrix* notation...
Back
Top