Geometric Distribution: Finding Specific p Value for Mean Calculation

umzung
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Homework Statement
The number of items bought by each customer entering a bookshop is a random variable X that has a geometric distribution starting at 0 with mean 0.6.
Find the value of the parameter p of the geometric distribution, and hence write down the probability generating function of X.
Relevant Equations
$$q/(1-ps)$$
I know the p.g.f. of X is $$q/(1-ps)$$ and that the mean is $$p/q$$, but how do I find a specific value for p here?
 
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umzung said:
Homework Statement:: The number of items bought by each customer entering a bookshop is a random variable X that has a geometric distribution starting at 0 with mean 0.6.
Find the value of the parameter p of the geometric distribution, and hence write down the probability generating function of X.
Homework Equations:: $$q/(1-ps)$$

I know the p.g.f. of X is $$q/(1-ps)$$ and that the mean is $$p/q$$, but how do I find a specific value for p here?

What are ##p, q## and ##s## here?
 
PeroK said:
What are ##p, q## and ##s## here?
$$p$$ is the probability, $$q$$ is (1 - probability) and $$s$$ is a dummy variable, not a random variable.
 
umzung said:
$$p$$ is the probability, $$q$$ is (1 - probability) and $$s$$ is a dummy variable, not a random variable.
Okay, so the mean is ##q/p = (1-p)/p##. Do you know the mean in this case?
 
Got it, thanks.
 
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