MHB Geostationary Orbits: Benefits & Challenges

AI Thread Summary
The discussion focuses on calculating the length of AC in a geostationary orbit scenario. The calculation involves using the formula for circumference, C = π * d, and applying the Pythagorean theorem to find BC. Participants confirm that the length of AC is 84,300 km, which includes the Earth's radius and the altitude of the orbit. The altitude of 35,800 km above Earth's surface is emphasized in the calculation. The conversation illustrates the straightforward nature of the calculations involved in determining distances in geostationary orbits.
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Hi, everyone can you help me with this question, please?
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(i) This calculation is straightforward ... what do you get for the length of AC?

(ii) recall $C = \pi \cdot d$, where $d$ is the length of the orbital diameter AC.

(iii) $BC = \sqrt{|AC|^2-|AB|^2}$

(iv) note ... $\cos(\angle{BAC}) = \dfrac{|AB|}{|AC|}$. Use inverse cosine on your calculator to determine the angle measure.
 
skeeter said:
(i) This calculation is straightforward ... what do you get for the length of AC?

(ii) recall $C = \pi \cdot d$, where $d$ is the length of the orbital diameter AC.

(iii) $BC = \sqrt{|AC|^2-|AB|^2}$

(iv) note ... $\cos(\angle{BAC}) = \dfrac{|AB|}{|AC|}$. Use inverse cosine on your calculator to determine the angle measure.

(i) for this one i got 84.300 is it right ?
 
Yes. Since the orbit is 35,800 km above the Earth surface, the distance from the Earth's surfacr to C, although it is not shown in the picture is also 35,800 km so the distance from A to C is 35,800+ 12,700+ 35,800= 84,300 km.
 
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