Given a canonical transformation, how does one find its type?

AI Thread Summary
The discussion revolves around determining the type of a given canonical transformation without needing to find a generator explicitly. It suggests that one can analyze the transformation by attempting to express the coordinates in terms of a specific set, rather than starting from Hamilton's principle. A proposed approach involves testing various coordinate sets to see if they allow for a valid generating function. The transformation's complexity is highlighted, indicating that some coordinate combinations may not yield a suitable generating function. Ultimately, exploring different coordinate sets is essential for classifying the transformation type effectively.
mjordan2nd
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I'm given the following transformation

X=x \cos \alpha - \frac{p_y}{\beta} \sin \alpha
Y=y \cos \alpha - \frac{p_x}{\beta} \sin \alpha
P_X=\beta y \sin \alpha + p_x \cos \alpha
P_Y=\beta x \sin \alpha + p_y \cos \alpha

and I'm asked to find what type(s) of transformation it is. I'm not sure how to go about doing this without being given a generator. Do I basically try and find a generator? If so, how do I do this. Do I start from Hamilton's principle and try the definition of each type of generator?
 
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Do I basically try and find a generator?

Not quite, that is a lot more work. You don't have to actually find the generator to determine what type it should be.

If so, how do I do this. Do I start from Hamilton's principle and try the definition of each type of generator?

Say, for the sake of argument, the generator F is a function of p_x,y,X,Y (it's not) so that F=F(p_x,y,X,Y). This means that you would be able to write the other coordinates (namely p_y,x,P_x,P_y) in terms of these ones. I can see that this type of generating function won't work since when I try to write P_y I find (you'll need to invert the transformation to see this):
<br /> P_y = x\beta \sin\alpha + p_y\cos\alpha = \left(X\cos\alpha + \frac{\sin\alpha}{\beta}P_y\right) \beta\sin\alpha + p_y\cos\alpha<br />
and that simplifies to P_y=X\beta\tan\alpha + p_y\sec\alpha. Therefore, I cannot write P_y as a function of only those chosen coordinates. Try something else and see if you can find a coordinate set that works---then you will know what type of generating function you can have.
 
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