Heat of Combustion for C6H4O2: q (kJ/g) & q (kJ/mol)

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To calculate the heat of combustion for quinone (C6H4O2), first determine the temperature change in the calorimeter, which is 7.13 degrees C. The total heat absorbed by the calorimeter is then calculated using its heat capacity, resulting in 56.63 kJ. Dividing this by the mass of the quinone sample (2.200 g) gives the heat of combustion per gram as approximately 25.77 kJ/g. To find the heat of combustion per mole, convert the mass to moles using the molar mass of quinone, yielding about 144.14 kJ/mol. This process illustrates the necessary calculations for determining the heat of combustion values.
ahappel
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I am needing help on some homework questions:

A 2.200 g sample of quinone, C6H4O2, is burned in a bomb calorimeter whose total heat capacity is 7.854 kJ/ degrees C. The temperature of the calorimeter increases from 23.50 degrees C to 30.63 degrees C.

1. What is the HEAT OF COMBUSTION PER GRAM of quinone? (in kJ/g)

2. Per mole of quinone? (in kJ/mol)
 
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according to the rules in physics forum, we can't help those that didnt show their efforts. We are just guiding, not doing all the homework for you. you must at least show your way of calculations before we can help you.
 

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