Help in rearranging a formulae

  • Thread starter Thread starter Fornicis
  • Start date Start date
  • Tags Tags
    Formulae
AI Thread Summary
The discussion centers on rearranging the formula PAvail = 1/2 ρAv^{3}C_{p} to isolate v. The user initially derived v^3 = (2PAvail) / (ρACp) and suggested taking the cube root of both sides. Participants clarified that "PAvail" refers to a single variable, despite initial confusion about its representation. There was also a minor correction regarding the use of "formulae" as the plural of "formula." The conversation emphasizes the importance of accuracy in mathematical rearrangements.
Fornicis
Messages
2
Reaction score
0
Hi all,

I was wondering if anyone could give me a hand in rearranging the following formulae to make v the subject?

PAvail = 1/2 ρAv^{3}C_{p}

This isn't for homework, its simply something I'm interested in and I would be immensely grateful to anyone who could do this for me.

Oh and before anyone says, I have tried to myself but I just want a second opinion as what it came out with for me seemed a bit off
 
Mathematics news on Phys.org
v3 = (2PAvail) / (ρACp)
and then take the cube root of both sides.

Is "PAvail" five different variables, or two, or one? Hard to tell... Anyway, same answer in any case.
 
Thats similar to what I got, though less brackets which could have resulted in miscalculations, and in this case its just one but as you said, it can be interchangeable, and that part is key :) thank you very much
 
Fornicis said:
Hi all,

I was wondering if anyone could give me a hand in rearranging the following formulae to make v the subject?

PAvail = 1/2 ρAv^{3}C_{p}
Minor point: this is a formula. Formulae is the plural of formula.
Fornicis said:
This isn't for homework, its simply something I'm interested in and I would be immensely grateful to anyone who could do this for me.

Oh and before anyone says, I have tried to myself but I just want a second opinion as what it came out with for me seemed a bit off
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...
Is it possible to arrange six pencils such that each one touches the other five? If so, how? This is an adaption of a Martin Gardner puzzle only I changed it from cigarettes to pencils and left out the clues because PF folks don’t need clues. From the book “My Best Mathematical and Logic Puzzles”. Dover, 1994.

Similar threads

Back
Top