Help in Solving a problem using F.T.C

  • Thread starter lilypeach
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In summary, the conversation discusses using the Fundamental Theorem of Calculus to evaluate a definite integral. The function being integrated is 5/(x^2+1). The steps to evaluate the integral are provided, including taking the antiderivative of tan^-1(x) and plugging in the limits of -1 and 1. The final answer is discussed, with a reminder to use radians when working with trigonometric functions.
  • #1
lilypeach
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Hi, here's my problem



Use the Fundamental Theorem of Calculus to evaluate the definite integral.
from the int. of -1 to 1, with the function being 5/x^2+1

= 5 int. 1/x^2+1
= 5 int. tan^(-1)(x)
= 5 x tan^-1(x)
Plug in 1 and -1...subtract...= 450, except it's wrong.

I've gotten as far as 5 int. tan^-1(x), and I get 450 once I plug in the limits, Am I missing anything?
 
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  • #2
lilypeach said:
Hi, here's my problem
Use the Fundamental Theorem of Calculus to evaluate the definite integral.
from the int. of -1 to 1, with the function being 5/x^2+1

= 5 int. 1/x^2+1
You need parentheses if you mean an integrand of 1/(x2+1)
= 5 int. tan^(-1)(x)

And if you have taken the antiderivative, you shouldn't still have the "int" in front.
= 5 x tan^-1(x)

And where did the x in front come from?

Plug in 1 and -1...subtract...= 450, except it's wrong.

I've gotten as far as 5 int. tan^-1(x), and I get 450 once I plug in the limits, Am I missing anything?

That last antiderivative, somehow, is actually correct. But remember in derivatives and integrals of trig function, x is always in radians.
 
  • #3
excellent, got it.

Thanks a million.
 

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