Help Me Solve Matrix: Show B†A† = C†

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Please HELP! Matrix!

Please help me with the below question! I have no idea how to solve this, if someone could please help me with a solution and explain what they did and how they did it, it would be such a BIG help! Thanks! :)


If A is an m×n matrix with (i, j)-entry aij , let A† be the n×m matrix with (i, j)-entry
aji. Show that

(i) if the product C = AB is defined, then so is B†A†,
(ii) B†A† = C†.
 
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well can you define B ??
 


Thats all the question says, so confused :confused:
 


since C =AB is defined then the matrix AB is defined thus B is defined to be a n x c matrix where c is any number
since A† be the n×m matrix so B† is defined as a c x n so B† A† is defined as a c x m matrix therefore B† A† is defined
 


okay second part comes from the first part if C is AB then it is a m x c matrix use A† is an n x m matrix with (i, j)-entry aij mulitply with B† by saying that B is a c x n matrix with (i, j)-entry bij and mulitply them you will get your answer but one note i didnt give you details so you have to define each matrix
 


can anyone elaborate on this? i still don't get Elabed Haidar's answer. Sorry
 
The world of 2\times 2 complex matrices is very colorful. They form a Banach-algebra, they act on spinors, they contain the quaternions, SU(2), su(2), SL(2,\mathbb C), sl(2,\mathbb C). Furthermore, with the determinant as Euclidean or pseudo-Euclidean norm, isu(2) is a 3-dimensional Euclidean space, \mathbb RI\oplus isu(2) is a Minkowski space with signature (1,3), i\mathbb RI\oplus su(2) is a Minkowski space with signature (3,1), SU(2) is the double cover of SO(3), sl(2,\mathbb C) is the...
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