Simplifying Dimensional Analysis for Unit Conversions

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Dimensional analysis helps in unit conversions by focusing on the relevant units for the problem at hand, ensuring that only compatible units are combined. When multiplying quantities with different units, such as volume in cubic meters and inverse cubic meters, the units can cancel out, resulting in a unitless number. It's crucial to avoid adding or subtracting terms with different powers, as this leads to nonsensical results. Understanding these principles allows for easier manipulation of units in more complex problems. Mastering dimensional analysis can significantly enhance problem-solving skills in physics and math.
Beholder
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Hello I'm learning physics and also brushing up on some math (its been 10yrs) and I encountered difficulty in understanding Dimensional analysis. I don't really understand how they know what number goes on top or what goes on bottom. I've read some explaintations but they just confused me more, one for instance was using the example that 1/6th times 6 over 1 = 1, so what? what are they trying to show me here I'm not catching on. If they give me a fairly simple word problem where you have to convert different units I can do it in my head but I would like to understand D.A. in order to solve more complex problems with more ease. Can anyone offer some help?
 
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It's not too difficult.

If you are trying to work some quantity out then the idea is to look at what units it would be measured in. For example if you have something where you know that it will be measured in length squared then you don't need to bother looking at time or energy as a variable.

Similarly it wouldn't make sense to add metres squared to metres cubed and things like that.
 
Beholder said:
... one for instance was using the example that 1/6th times 6 over 1 = 1, so what? what are they trying to show me here I'm not catching on. ...
Let's take meters. Meter times meter times meter = meter cubed.

If you invert meter cubed you'd get inverse meters cubed: 1/ \text{m}^3 = \text{m}^{-3}

First of all, you may not add or subtract terms with different Powers. For ex., if A (for "area") is measured in meters squared (e.g. A = 1500\text{m}^2) and V (for "volume") is measured in meters cubed (e.g. V = 16000\text{m}^3), then A + V does not make any sense; it's like "adding apples and oranges."

Now, let's say you are multiplying a quantity (say V = 16000\text{m}^3) measured in meters cubed with another quantity measured in inverse meters cubed (say W = 9\text{m}^{-3}). Then, V times W = 144000 which is a unitless number (a "pure number"). It's as if the meters cubed and inverse meters cubed "cancel out." Just like 1/3 would cancel 3 out. That's what 1/6 times 6 = 1 is aiming to represent in my opinion.
 
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Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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