Help setting up a CHEM E problem

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The discussion revolves around determining the minimum inside diameter of a pipe needed to feed three fillers into a pharmaceutical emulsion without exceeding a velocity of 1.2 m/s. The total mass flow rate of the fillers is calculated to be 14,100 kg/h, which converts to 235 kg/s. The volumetric flow rate is then found to be 0.224 m^3/s using the density of the emulsion. The calculation for the pipe diameter involves using the relationship between mass flow rate, volumetric flow rate, and velocity. Ultimately, a diameter of 2.75 cm is proposed as the solution, which is confirmed by a class partner's calculations.
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[SOLVED] help setting up a CHEM E problem

Homework Statement



Three fillers used in packaging a pharmaceutical emulsion (ro = 1050kg/m^3) are fed from a single product line. One filler has a capacity of 2700kg/h, the second operates at
4600 kg/h and the third at 6800 kg/h. The emulsion is susceptible to damage at velocities greater that 1.2m/s, due to shear at the pipe wall. What size (ie minimum inside diameter) in cm should be used to feed the fillers through a single line?

Homework Equations


ro = mass flow rate / volumetric flow rate and do i use the v1A2=v2A2 where v = velocity and A = area to determine the size of thepipe.

b]3. The Attempt at a Solution [/b]

ok so i add the mass flow rates and get 14,100 kg/h then i thought i should make this kg/s so i got 235 kg/s then into volumetric flow 235/1050 = 0.224 m^3/s

now i draw a blank why can't i remember how to make m^3 into m do i cube root or ?? and then do i use the v1a1=v2a2 do set up my pipe??
 
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well I made a mistake reading the problem i was assuming that the three fillers were supplying the single pipe. The only thing to determine is what size of pipe is needed to supply the three fillers not to exceed 1.2 m/s.

My class partner has made this conclusion

(2700 kg/h) / (3600 s) / (1050 kg/m^3) / (1.2 m/s) / pi / sqrt *2

so we have the pipe equal to 2.75 cm when all is said and done does anyone agree with this conclusion
 
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