Help w/ using Blevins formula for natural frequency of a cylinder

AI Thread Summary
The discussion focuses on using Blevins' formula to calculate the natural frequency of a hollow cylinder, specifically seeking clarification on determining mass per unit length (m) and the area moment of inertia (I). For a thin-walled cylinder, the correct formula for mass per unit length is derived from the area multiplied by the mass per unit volume, specifically using the outer diameter, wall thickness, and density. Participants debate the appropriate formula for I, with two options presented: one based on the outer and inner diameters and another for thin-walled tubes. The need for precise definitions and correct formulas is emphasized to ensure accurate calculations. Overall, the thread seeks to clarify these key parameters for effective application of the formula.
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I came across this formula by Blevins for calculating the natural frequency of a hollow cylinder and was hoping that someone could answer a question I have for calculating the mass per unit length (m). Here's the formula:

f = A/(2*pi*L^2)*sqrt(E*I/m)

A= 9.87 for first mode
I = Area Moment of Inertia (m^4)
m= Mass per Unit Length (kg/m)


In this formula what equation should I use to determine the m (mass per unit length) for a thin-walled cylinder? Also, does I = pi/64*(d^4-di^4) in this case?
 
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Does anyone have any insight on this? In the original data where I found this formula it states that "m = mass per unit length of beam (kg/m)". I take it that it's not referring to the mass density of the beam itself but rather the mass per unit length as described. If so then is this actually the area X the mass per unit volume (i.e., PI*d*t*density)?

As for the I (Area Moment of Inertia) I have found two formulas but can someone tell me which is the correct one to use for this application? Here's what I've found:

I = PI * (OD^4 - ID^4)/64

I = PI*d^3*t/8 (for a thin wall round tube)

Any help would be greatly appreciated.
 
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