Help with length contraction and relativistic momentum please

AI Thread Summary
The discussion centers on calculating the height of a woman moving at relativistic speeds, given her proper height, mass, and measured relativistic momentum. The key equations involved are for length contraction and relativistic momentum. The participant initially struggles to find the speed (v) needed to solve for height but eventually realizes that they can derive v from the momentum equation. After some back-and-forth, they successfully work through the algebra and arrive at a solution. The conversation highlights the importance of understanding relativistic equations and algebraic manipulation for solving physics problems.
shamille
Messages
4
Reaction score
0

Homework Statement


A woman is 2.0 m tall and has a mass of 60 kg. She moves past an observer with the direction of the motion parallel to her height. The observer measures her relativistic momentum to have a magnitude of 2.30x1010 kg·m/s. What does the observer measure for her height?

Homework Equations


L=Lo √1 - (v2/c2)
p=mv/√1 - (v2/c2)

The Attempt at a Solution


I'm pretty sure that these are what the variables are
Lo= 2.0m proper length
p=2.3x1010
m=60kg
we want to solve for L

my problem is I don't know what v is, if I did i could find it.

I saw that L/Lo = mv/p
so L= Lomv/p right?

but i have no idea how to get v. i haven't had math in a while! any ideas or can you help me? I've tried an online equation solver for didn't work...
 
Physics news on Phys.org
You have p and m so you can solve the momentum equation for v.
 
well i got the answer as 1.24 but i had to use a function grapher and play around with the x and y mins and maxes to find what speed gives a momentum of 2.3E10! which was 0.79C

but i still want to know how to do this because there will be a test and i won't have the internet to help me

thanks in advance
 
Cyosis said:
You have p and m so you can solve the momentum equation for v.

yes but this is relativistic momentum not p=mv but
p=mv/√(1 - (v2/c2))
and i couldn't solve it for v... is it because I'm crap at math?
can you walk me through how to solve for it? maybe it's more algebra than physics but...
 
shamille said:
yes but this is relativistic momentum not p=mv but
p=mv/√(1 - (v2/c2))

There are still only three variables of which you know two.You know how to solve quadratic equations I assume?

<br /> \begin{align}<br /> p=mv \gamma=\frac{mv}{\sqrt{1-\frac{v^2}{c^2}}}<br /> \\ <br /> p\sqrt{1-\frac{v^2}{c^2}}=mv<br /> \\ <br /> p^2(1-\frac{v^2}{c^2})=m^2v^2<br /> \end{align}<br />

Can you solve it from here on?
 
yes! wow as soon as i wrote that last message i figured it out. I don't know where my head was before... and then I used a - instead of +... gahhh

i'm sorry!

but thank you so much
 
You're welcome.
 
Back
Top