How can [a+,[a+,a]]=0 be proven in the quantum oscillator system?

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The discussion focuses on proving the commutation relations [a+, [a+, a]] = 0 and [a, [a+, a]] = 0 in the context of quantum oscillators, where a+ is the raising operator and a is the lowering operator. Participants reference key formulas and identities, including the Jacobi Identity and the properties of ladder operators. Attempts to solve the problem involve applying these mathematical frameworks but seem to lead to confusion regarding the correct topic. The conversation highlights the challenges in understanding the application of these identities in quantum mechanics. Overall, the need for clarity in the topic and the mathematical approach is emphasized.
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Homework Statement


Actually the question is two long and I'll be done if I can show that
[a+,[a+, a]=0 and similarly
[a,[a+, a]=0
where a+ is the raising and a is the lowering ladder operator in quantum oscillator.

Homework Equations


I tried the formulas
[A,[B,C]]= -[C,[A,B]] -[B,[C,A]] and
a\psin=\sqrt{n}\psin-1
a+\psin=\sqrt{n+1}\psin+1

The Attempt at a Solution

 
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meanyack said:
I tried the formulas
[A,[B,C]]= -[C,[A,B]] -[B,[C,A]] and

The Jacobi Identity is [A,[B,C]] = [[A,B],C] + [B,[A,C]]
 
why can't I see a button "delete topic" because this is the wrong topic, the original one is the other one
 
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