How can I calculate the max velocity for a car climbing a 15-degree hill?

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To calculate the maximum velocity of a 3000-lb car climbing a 15-degree hill with an 80-hp engine, one must consider the power output in relation to gravitational potential energy. The engine's power translates to approximately 60 kJ/s, which is the rate at which energy is converted to maintain motion. The key is to determine the rate of elevation gain that this power can support. Understanding the relationship between energy per unit time and the change in elevation will help in solving the problem. This approach will yield the maximum velocity for the car on the incline.
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velocity problem! NEED HALP ASAP!

hellloooo physics friends ok here's the issue:

A 3000-lb. car has an engine which can deliver 80-hp. to the rear wheels. What is the max velocity at which the car can climb a 15-degree hill?

We were told this must be answered tomorrow for part of our final, and I absolutely have no idea what to do. Help would be greatly appreciated!

-zac
 
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Are you sure it is velocity and not acceleration?
 
The velocity up the hill specifies a certain change in evelation per unit time.

Change in gravitational potential energy can be defined in terms of change in evelation. Since you know how fast the elevation is changing, you know how fast the gravitational potential energy is changing.

Energy per unit time is power.

To keep the car moving at a steady velocity up the hill, the engine is converting energy in the fuel into increasing gravitational potential energy at a rate of 80 hp, or about 60 kJ/s: http://www.google.com/search?hl=en&q=80+hp+in+joules/second&btnG=Google+Search

All you have to do is figure out what rate of elevation gain would require 60kJ/s to maintain.

- Warren
 
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