No. 8.73m/sec was the total magnitude of the initial velocity. Each component, accordingly would be less than that.coffeemanja said:Yes, if you look at the diagram as at is in the problem...origin is the bike, x to the right, y -up. The Vi forward component is equal 8,73...no?
Without angles, how do you properly add the vectors?coffeemanja said:If we look at the situation as flat diagram, vi(flying apple) is 8,73. Vb is 5,6. Given that relative velocity = v object (Apple)-v observer(me on the bike). I find angles irrelative.
For Vi= xi+yjRUber said:Without angles, how do you properly add the vectors?
The bike is not traveling in the same direction as the apple, so subtraction of magnitudes does not work.
Vi=Vxi+Vyicoffeemanja said:For Vi= xi+yj
What about Vzi?coffeemanja said:Vi=Vxi+Vyi
I am looking at situation schematicly(flat). All vectors then have only two components.RUber said:What about Vzi?
Then I get 8,2. 8,2-5,6=2,6 is then relative velocity.RUber said:Okay. Then you need to flatten the initial velocity vector, which has 3 dimensions. You can do this by multiplying by the cosine of the elevation angle.
I will look at it tomorrow with fresh eyes. Do not want to bother you anymore here. Thank you.RUber said:No. The bike is not moving in the direction of the trash can.
The bike is moving forward.
The forward velocity is 4/5 of the flat velocity.
RUber, be proud. You are great! I got it, was too tired to understand.RUber said:No. The bike is not moving in the direction of the trash can.
The bike is moving forward.
The forward velocity is 4/5 of the flat velocity.
Thanks. Glad it made more sense after some sleep.coffeemanja said:RUber, be proud. You are great! I got it, was too tired to understand.